Mekanika Kekuatan Material "BATANG AKSIAL"

Dik : A =100mm
         E = 50
Tentukan - r ab, rbc, rcd
              - δ total





∑f = 0
Fa + 50 - 15 – 20 = 0
Fa = 5 kn

∑f =0
Fab – 5=0
Fab = 5 kn Fbc = 55 kn
                                             Ab = Fab : A = 5000 : 100 = 50 mpa


∑f = 0
Fbc - 50 – 5 = 0
Fbc = 55 kn
rFbc : A = 55000 : 100 = 550 mpa

∑f =0
Fcd – 20=0
Fcd = 20 kn
                                         rAb = Fcd : A = 20000 : 100 = 200 mpa

δ total = 1 : E [ ( rab x L ab)+( rbc x Lbc ) + ( rcd x Lcd ) ]
           = 1 : (5000 mpa) x [ (50 x 20)+(550 x 40)+(200 x 20)]
           = 1 : (5000 mpa) x ( 63000 mpa.m)
           = (63000 mpa.m) : (5000 mpa)
           = 12.6 M

*** KETERANGAN: ***
r = sigma kecil